First, we write our reaction:
PbO + 2HNO3 ====> Pb(NO3)2 + H2O (it is already balanced)
We need the mass of Pb(NO3)2 to be produced, from 25 g of HNO3
Procedure: Stoichiometry
Data:
The molar mass of PbO=223.2 g/mol
The molar mass of HNO3 =63.01g/mol
The molar mass of Pb(NO3)2 =331.2g/mol
The molar mass of H2O=18.0g/mol
According to our reaction, we proceed like this:
2 x 63.01 g HNO3 ------- 1 x 331.2 g Pb(NO3)2
25 g HNO3 -------- X
X = (25 g x 1 x 331.2 g)/ 2 x 63.01 g
X = 65.70 g
Answer: 65.70 g Pb(NO3)2