Question

How to solve (2.31*10^-6)+(5.87*10^-4)

Answer 1

We want to calculate the following

`2.31\cdot10^(-6)+5.87\cdot10^(-4)`

Using the properties of exponents, we have that

`10^(-6)=10^(-4)\cdot10^(-2)`

So we have

`2.31\cdot10^(-6)+5.87\cdot10^(-4)=2.31\cdot10^(-2)\cdot10^(-4)+5.87\cdot10^(-4)`

So, if factor 10^-4 on the right side, we have

`10^(-4)(2.31\cdot10^(-2)+5.87)`

Note that

`2.31\cdot10^(-2)=0.0231`

Then,

`5.87+2.31\cdot10^(-2)=5.87+0.0231=5.8931^{}`

So we have that

`2.31\cdot10^(-6)+5.87\cdot10^(-4)=5.8931\cdot10^(-4)`