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Two cars are traveling down the highway at the same speed. If the first car increases its speed by 10 kilometers per hour, and the second car decreases its speed by 10 kilometers per hour, then the first car will travel the same distance in two hours that the second car travels in three hours. What is the original speed of the cars?

User Dazak
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2 Answers

17 votes
17 votes
No clue if this is correct but this is what i found online
let s = the original speed
Write a distance equation; dist = time * speed
3(s-10) = 2(s+10)
3s - 30 = 2s + 20
3s - 2s = 20 + 30
s = 50 km/hr is the original speed
:
:
confirm this, find the distances
3(50-10) = 120 km
2(50+10) = 120 km
User QQQuestions
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3.3k points
15 votes
15 votes

Answer:

50mph

Explanation:

Say for example car A increases by 10 miles per hour and car B decreases by 10 miles per hour. If car A2 = car B3 then by eliminating a few numbers and finally get to 50 you get the following equation.

A = 50+10

b = 50-10

A = 60

B = 40

A2 = 120

B3 = 120

120 = 120

User Kumaresan Sd
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3.0k points