Question

Part BSince the equations for both triangles have a2 + b2, you can think of the two equations for cand n as a system of equations. Substitute what a? +b2 equals in the first equation for o? + b2 in the second equation. After you substitute, what equation do you get?Part CNow, take the square root of both sides of the equation from part B and write the resulting equation Part D Is there any way for this equation to be true?How?Part EWhat does this show about the relationship between the two triangles?Part FDoes this mean that triangle 1? Why or why not?Sorry if its a lot of questions but I really need this to be answer

Answer 1

Part B

We know,

`\begin{gathered} a^2+b^2=c^2 \\ a^2+b^2=n^2 \end{gathered}`

Now, we substitute a^2+b^2=c^2 in the second equation

`\begin{gathered} a^2+b^2=n^2 \\ c^2=n^2 \end{gathered}`

So, the new equation is c^2 = n^2

Part C

Now, taking the square root of both sides of the equation from part B, we get

`\begin{gathered} \sqrt[]{c^2}=\sqrt[]{n^2} \\ c=n \end{gathered}`

Part D

The equation obtained is true thanks to the Pythagorean theorem, because the corresponding legs in both triangles are of equal measure, we will obtain that their hypotenuse is also equal.

You can see that the 90° angles is conformed by 2 sides, these sides are the legs and the last side is the hypotenuse.

Part E

This means that the 2 triangles are equal, they have 3 sides equals.

The triangles also meet the criterion that explains that if two sides and the angle opposite the longest side are equal, the triangles are equal.

Part F

Yes, the triangle 1 is a rigth triangle because this has a right angle, that is, a 90 degree angle