Part A: Solving for the slope.
Recall that given two points in the line, the slope of a linear function is given by the equation

In this instance we will be using points (0,-4) and (1,-5).
Substitute these two points and we get

Therefore, the slope of the linear function is -1.
Part B: Solving for y-intercept
The y-intercept is the value of y, when x = 0.
In the given table, when x = 0, y = -4. Therefore, the y-intercept of the linear function is -4.
Part C: Equation of the line
The slope-intercept form of a line equation is in the form

As solved earlier, the slope is -1, and the y-intercept is -4.
Substitute m = -1, and b = -4, to the slope-intercept form. The equation of the line therefore is
