Question

To rent a certain meeting room, a college charges a reservation of $45 and an additional fee of $8.30 per hour. The history club wants to spend less than $111.40 on renting the meeting room. What are the possible amounts of time for which they could rent the meeting room? Use t for the number of hours of the meeting room is rented, solve your inequality for t

Answer 1

The possible amounts of time for which they could rent the meeting room is less than 8 hours.

STEP - BY - STEP EXPLANATION

What to find?

Possible amounts of time for which they could rent the meeting room.

Given:

• Reservation fee = ,$45

,

• Rent per hour charged = ,$8.30

,

• Number of hours the history club wants to spent = less that ,$111.40

Let the number of hours the meeting room is rented be t hours.

Hence, rent charged for t hours = $8.30t

Total charges = rent charged for t hours + reservation fee

=8.30t + 45

But from the question, the history club wants to spent less than $111.40 on renting the meeting room.

We will now have,

8.30t + 45 < 111.40

We can now proceed to solve for t.

Subtract 45 from both-side of the above inequality.

8.30t < 111.40 - 45

8.30t < 66.4

Divide both-side of the inequality by 8.30

`\frac{\cancel{8.30}t}{\cancel{8.30}}<(66.4)/(8.30)`
`t<8`

Therefore, the possible amounts of time for which they could rent the meeting room is less than 8 hours.