The given equation is expressed as
y = x^2 - 6x - 16
We would factorize the equation and find the roots
The first step is to equate it to 0. We have
x^2 - 6x - 16
Next, we would find two terms such that their sum or difference is - 6x and their product is - 16^2. These terms are 2x and - 8x. By inserting these terms in the equation, we have
x^2 + 2x - 8x - 16 = 0
By factorising, we have
x(x + 2) - 8(x +2) = 0
(x - 8)(x + 2) = 0
x - 8 = 0 and x + 2 = 0
x = 8 and x = - 2
The roots of the equation are the values of x where the curve cuts the horizontal axis. Each interval on the horizontal axis is 2 units. Locating x = 8 and x = - 2 in the options, the correct option is C
Graph C is correct