Question

A 1,350 kg package is dropped from a plane from a height of 760meters. What is its potential energy right before it starts to fall?

Answer 1

Given:

Mass (m) of package = 1350 kg

Height, h = 760 meters

Let's find the potential energy right before the object starts to fall

To find the potential energy, apply the formula below:

`P.E=m\ast g\ast h`

Where:

m = 1350 kg

h = 760 meters

g is the acceleration due to gravity = 9.8 m/s^2

Substitute values into the equation:

`\begin{gathered} PE=1350\ast9.8\ast760 \\ \\ PE=10054800\text{ J }\approx10.0548\text{ MJ} \end{gathered}`

Therefore, the potential energy right before the object starts of fall is 10.0548 megajoules.

ANSWER:

10.0548 MJ