Question

Combine the following fractions by addition or subtraction as directed.

Answer 1

Answer:
`(6)/(y^2-xy)-(6)/(x^2-xy)=(6(x+y))/(xy(y-x))`

Step-by-step explanation:

Combining the fractions, we have:

`\begin{gathered} (6(x^2-xy)-6(y^2-xy))/((x^2-xy)(y^2-xy)) \\ \\ =(6x^2-6xy-6y^2+6xy)/((x^2-xy)(y^2-xy)) \\ \\ =(6x^2-6y^2)/(x(x-y).y(y-x)) \\ \\ =(6(x-y)(x+y))/(-xy(x-y)^2) \\ \\ =(-6(x+y))/(xy(x-y)) \\ \\ =(6(x+y))/(xy(y-x)) \end{gathered}`