Question

Find the vertex of the function given below. у= 2х^2 + 4х+1 ОА. (1,7) ов. (-1, -1)с. (3, -4) D. (-4, 9)

Answer 1

Given the function:

`y=2x^2+4x+1`

To find the vertex, first use the formula below to find x:

`x\text{ = }(-b)/(2a)`

Where b = 4 and a = 2 from the equation.

we have:

`x\text{ = }(-b)/(2a)=(-4)/(2\ast2)\text{ = }(-4)/(4)\text{ = -1}`

Since x = -1, to find y, substitute x for -1 in the equation:

`\begin{gathered} y=2x^2+4x+1 \\ \\ \text{ = 2(-1)}^2+4(-1)+1 \\ \\ \text{ = 2 - 4 + 1 = }-1 \end{gathered}`

Therefore the vertex is: (-1, -1)

ANSWER:

(-1, -1)