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Ann has some dimes and quarters. If she has 27 coins worth a total of $3.45, how many of each type of coin does she have?

User Jason Jong
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1 Answer

3 votes

Variables

x: number of dimes

y: number of quarters

If she has 27 coins, then:

x + y = 27

Each dime is worth $0.1, each quarter is worth $0.25. All together the coins are worth $3.45, then:

0.1x + 0.25y = 3.45

Isolating x from the first equation:

x = 27 - y

Substituting this into the second equation:

0.1(27 - y) + 0.25y = 3.45

0.1*27 - 0.1y + 0.25y = 3.45

2.7 + 0.15y = 3.45

0.15y = 3.45 - 2.7

0.15y = 0.75

y = 0.75/0.15

y = 5

And the value of x is:

x = 27 - 5

x = 22

She has 22 dimes and 5 quarters

User Westandy
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