Question

Enter an equation in standard form.slope=-7/2and (4, -14) is on the line.

Answer 1

`y+(7)/(2)x=0\Rightarrow s\tan dard\text{ form}`

Step-by-step explanation

Step 1

to find the equation use:

`\begin{gathered} y-y_1=m(x-x_1) \\ \text{where} \\ P(x_1,y_1)\text{ is a point of the line} \\ \text{and m is the slope} \end{gathered}`

Let

slope=-7/2

point= P(4,-14)

Step 2

replace,

`\begin{gathered} y-y_1=m(x-x_1) \\ y-(-14)=-(7)/(2)(x-4)_{} \\ y+14=-(7)/(2)x+(28)/(2) \\ add\frac{\text{ 7}}{2}x\text{ in both sides} \\ y+14+(7)/(2)x=-(7)/(2)x+(28)/(2)+(7)/(2)x \\ y+14+(7)/(2)x=14 \\ \text{subtract 14 in both sides} \\ y+14+(7)/(2)x-14=14-14 \\ y+(7)/(2)x=0\Rightarrow s\tan dard\text{ form} \end{gathered}`

I hope this helps you