Given a diameter LM and its coordinates.
The coordinate of the center is the midpoint of LM
Midpoint = [(x1 + x2)/2, (y1 + y2)/2]
Coordinate of the center = [(-4+12)/2, (-8+4)/2]
Coordinate of the center = (4, -2)
Now to get the length of the radius, get the distance of LM and divide it by 2 :
![d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://img.qammunity.org/2023/formulas/mathematics/college/be685jmxw05hm2tq94m5iuge2xjynn1hfn.png)
![d=\sqrt[]{(4+8)^2+(12+4)^2}](https://img.qammunity.org/2023/formulas/mathematics/college/i1wjqgsm5n8k2fdnckiu88ntn3myh1i4ut.png)
d = 20
and the radius is 20/2 = 10
Now we have the center at (4, -2) and a radius of 10
The standard equation of a circle is :
(x-h)^2 + (y-k)^2 = r^2
where h and k are the center of the circle (h, k)
So the equation will be :
(x-4)^2 + (y+2)^2 = 10^2
or
(x-4)^2 + (y+2)^2 = 100