Question

What is KL to this question? I couldn’t figure it out!

Answer 1

The general equation of a circle is:

`(x-a)^2+(y-b)^2=r^2.`

Where r is the radius and (a, b) is the centre.

We have the circle Q represented by the following equation:

`(x-11)^2+(y+15)^2=7.`

To identify the elements of the circle, we write the last equation as:

`(x-11)^2+(y+15)^2=(\sqrt[]{7})^2.`

Comparing this equation we the general equation above, we see that the radius is:

`r=\sqrt[]{7}.`

Segment KL is the diameter of the circle. Because the diameter is two times the radius, we have:

`KL=d=2r=2\cdot\sqrt[]{7}.`

Answer

C. 2√7