Question

3.00x10^22 molecules of CH4 gas are held in a container at 1.20atm, at 27 ° C. Determine the volume of this container in L. R= 0.0821 (atm*L)/(mol*K)

Answer 1

In this question, we have to find the volume of a gas in a container, and in order to do that, we will be using the Ideal gas Law formula, which shows perfectly the correlation between temperature, pressure, volume and number of moles, the formula is:

PV = nRT

We have:

P = 1.20 atm

V = ?

n = we have the value in atoms, we will need to find the number of moles with the value in atoms 3.00*10^22

R = gas constant, 0.082

T = temperature in kelvin, 300 K

Now to find the number of moles, we need to use the Avogadro's value, which is the total number of atoms in 1 mol of the atom, the value is 6.02*10^23 atoms

6.02*10^23 = 1 mol

3.00*10^22 = x moles

x = 0.05 moles of this gas

Now we can use the Ideal gas law formula:

1.20 * V = 0.05 * 0.082 * 300

1.20V = 1.23

V = 1.02 Liters of Volume