x is computed as follows:
cos(15°) = adjacent/hypotenuse
cos(15°) = 50/x
x = 50/cos(15°)
x = 51.8 ft
How far away is the Professor from the Skipper?
51.8 ft
y is computed as follows:
tan(15°) = opposite/adjacent
tan(15°) = y/50
tan(15°)*50 = y
13.4 ft = y
How far is the Professor from the base of the observation post?
13.4 ft