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Rodrunner · Answer 1 · 2023-12-09T10:52:08+0000

The area of the sector is derived as follows;

$\begin{gathered} \text{Area of sector=}(\theta)/(360)*\pi* r^2 \\ \text{Area}=(32)/(360)*3.14*27.1^2 \\ \text{Area}=(4*3.14*734.41)/(45) \\ \text{Area}=(9224.1896)/(45) \\ \text{Area}=204.981991111\ldots \\ \text{Area}\approx205\operatorname{mm} \end{gathered}$

Please note that the final answer has been rounded off to the nearest whole number.

The answer therefore is 205 square millimeters

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