Given,
Sin# = - 2/3
We would find # by finding the sine inverse of - 2/3. Thus,
Sin^-1(-2/3) = - 41.81 degrees
Considering option A,
Sec# = 3/root 5
Recall, Sec# = 1/Cos#
Thus,
1/Cos# = 3/root 5
By taking reciprocals,
Cos# = root5/3
# = Cos^-(root5/3) = 41.81
tan# = - 2/root5
# = tan^-1(-2/root5) = - 41.81
Since the first value is positive, this option is incorrect
For option B,
Cos# = root5/3
# =