We want to solve the following
![\text{ -2(6-3n)+27n =-3(n-8)}](https://img.qammunity.org/2023/formulas/mathematics/college/wkrigdumywfnzwnj5xra74n5w81ap6up0i.png)
First we distribute each multiplication on each side, so we get
![\text{ - 12 }+6n+27n=\text{ -3n+24}](https://img.qammunity.org/2023/formulas/mathematics/college/1byukulg65vlw59irzh77s7s2ehv2o601i.png)
If we operate on the left side, we get
![\text{ -12 +33n= -3n+24}](https://img.qammunity.org/2023/formulas/mathematics/college/3dgyymxvh2j85p229v2byceicyvjsxgecl.png)
Now, we add 3n on both sides, so we get
![24\text{ = -12+33n+3n = -12+36n}](https://img.qammunity.org/2023/formulas/mathematics/college/9onjfjurta6if0egfsplmgmasw6wvtpv22.png)
Then, we add 12 on both sides, so we get
![36n=24+12=36](https://img.qammunity.org/2023/formulas/mathematics/college/j2gt2lwlf2kzi3wl8ye8q8871mf4rle0ui.png)
Finally, we divide boths sides by 36, so we get
![n=(36)/(36)=1](https://img.qammunity.org/2023/formulas/mathematics/college/4barx6ymp3qrkeldno4dii3p25qzdw53nq.png)
So the value of n is 1