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16 votes
If 8 cakes cost $62.40, how much would 3 cakes cost?

2 Answers

6 votes

Solution:

Note that:

  • 8 cakes = $62.40

This question requires the knowledge of Unitary method.

Step-1: Divide 8 both sides of the equation to obtain the cost for 1 cake.

  • 8 cakes = $62.40
  • => 8/8 cakes = $62.40/8
  • => 1 cake = $7.80

Step-2: Multiply 3 both sides to find the cost of 3 cakes.

  • 1 cake = $7.80
  • => 3 cakes = $7.80 x 3
  • => 3 cakes = $23.40
User Pileup
by
8.4k points
3 votes

Answer:

$23.40

Explanation:

Given,

Cost price of 8 cakes = $62.40

So,

Cost price of 1 cake = $
(62.40)/(8)

Therefore,

Cost price of 3 cakes

= $(
(62.40)/(8) × 3)

  • [On dividing 62.40 by 8]

= $(7.80 × 3)

  • [On multiplying]

= $23.40

Hence,

The required cost of 3 cakes is $23.40 (Ans)

User Rohan Das
by
8.2k points

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