h = 60, x = 25 (option B)
Step-by-step explanation:
x/leg 1 =leg 1/ (x + 144)
leg 1 = 65
144/leg 2 = leg 2/(x + 144)
leg 2 = 156
To avoid a quadratic equation, we will go with the equation having leg 2
![\begin{gathered} (144)/(156)=(156)/(x+144) \\ \text{cross multiply:} \\ 144(x\text{ + 144) = 1}56(156) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/8ff4cz6ostydhedfo6v0os8mtis1koxlex.png)
![\begin{gathered} 144x\text{ + 20736 = 24336} \\ 144x\text{ = 3600} \\ x\text{ = 3600/144} \\ x\text{ = 25} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/s8qefs0mf8ik74hhfaepq60l9fj9i1cjmc.png)
To get height (h), apply geometric mean:
![\begin{gathered} (h)/(x)=(144)/(h) \\ h^2\text{ = 144(x)} \\ h^2=144(25) \\ h^2\text{ = 3600} \\ h\text{ = }\sqrt[]{3600} \\ h\text{ = 60} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/s3pdfakftivf4mm3nad82ygikjjoj4rh0p.png)
h = 60, x = 25 (option B)