45.2k views
2 votes
9)7 pointsWhat is the surface area of the jewelrybox that would need to be wrapped withwrapping paper?A. 146 cm2B. 292 cm2C. 336 cm2D. 672 cm217 cm6 cm8 cmОАОвOD

9)7 pointsWhat is the surface area of the jewelrybox that would need to be wrapped-example-1

1 Answer

2 votes

Given a box with dimensions l by w by h,

then the total surface area is given by


\text{total surface area = }2(lw+lh+wh)

In this case,


l=8\operatorname{cm},w=6\operatorname{cm},h=7\operatorname{cm}

Therefore,


\text{ total surface area = }2(8*6+8*7+6*7)=2(48+56+42)=2*146=292\operatorname{cm}^2

The right choice is B

9)7 pointsWhat is the surface area of the jewelrybox that would need to be wrapped-example-1
User WestFarmer
by
6.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.