First, the probability of a class attendee being a non-member and attending a barre class is
![P(Non\cap Barre)=(241)/(2317)](https://img.qammunity.org/2023/formulas/mathematics/college/uwq6bz624fa1p3ogl9nod20hcmchxmrmmj.png)
While the probability of class attendee being a member and attending a yoga class is
![P(Member\cap Yoga)=(232)/(2317)](https://img.qammunity.org/2023/formulas/mathematics/college/75v8bcjbdtinj1tt9o7aezy7zsuw4kr38u.png)
Finally, the probability of the first event or the second event is
![\begin{gathered} P((Non\cap Barre)\cup(Member\cap Yoga))=P(Non\cap Barre)+P(Member\cap Yoga) \\ =(232+241)/(2317)=(473)/(2317) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/xtsdzk3ci1vajmhatdc2tyynzwv0fnew94.png)
In a decimal expression,
![\Rightarrow P((Non\cap Barre)\cup(Member\cap Yoga))=0.204143\ldots\approx0.2041](https://img.qammunity.org/2023/formulas/mathematics/college/m370kx001ghiiky44wxgoik13ucbu7vw8f.png)
The answer is 473/2