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Find the equation for the line (-1,3) and (5,-5)

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We need to find the line equation for the line passing through (-1,3) and (5,-5).

First, we need to find the slope using the slope formula:


m=(y_2-y_1)/(x_2-x_1_)

Replace using P1(-1,3) and P2(5,-5).

Therefore:


m=(-5-3)/(5-(-1))=(-8)/(6)=-(4)/(3)

Then, we need to find the line :


y-y_1=m(x-x_1)

Use m= -4/3 and P1(-1,3). Then:


\begin{gathered} y-3=-(4)/(3)(x-(-1)) \\ y-3=-(4)/(3)x-(4)/(3) \\ y=-(4)/(3)x-(4)/(3)+3 \\ y=-(4)/(3)x+(5)/(3) \end{gathered}

Hence, the line equation is:


y=-(4)/(3)x+(5)/(3)

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