ANSWER
![y=-3x+10](https://img.qammunity.org/2023/formulas/mathematics/high-school/tsnv3777tmwmyz6t70h6ofdqfvnnp06eq8.png)
Step-by-step explanation
The general form of the equation of a line is:
![y=mx+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/smsb8cbft03lwblmi49nf2l6jby2ofxzws.png)
where m = slope
b = y-intercept
A line that is perpendicular to another line has a slope that is the negative inverse of the slope of the line.
Hence, the slope of the line we are looking for is:
![\begin{gathered} -(1)/((1)/(3)) \\ \Rightarrow-3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/wdmr4bdm7rgh49scj6vuhg3v6z2g6b6rye.png)
Now, we can apply the point-slope method to find the equation of the line:
![y-y_1=m(x-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/csobd57zth7rh9k4hz9amldzpq2owf0z4j.png)
where (x1, y1) = point that the line passes through
Therefore, the equation of the line is:
![\begin{gathered} y-4=-3(x-2) \\ y-4=-3x+6 \\ y=-3x+6+4 \\ y=-3x+10 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/789nphm5hwaljzro6op41s248ziugqdpoc.png)
That is the answer.