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1) Solve by substitution. Eq #1y = -2x - 9 Eq #2 y = 3x + 1
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1) Solve by substitution. Eq #1y = -2x - 9 Eq #2 y = 3x + 1

User Aminography
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\begin{gathered} y=-2x-9 \\ y=3x+1 \\ 3x+1=-2x-9 \\ 3x+1-1=-2x-9-1 \\ 3x=-2x-10 \\ 3x+2x=-2x-10+2x \\ 5x=-10 \\ (5x)/(5)=(-10)/(5) \\ x=-2 \end{gathered}

and for y


y=3\mleft(-2\mright)+1=-6+1=-5

answer: ( -2, -5)

User Sfeuerstein
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