Question

What is the slope of a line perpendicular to the line that contains the points (9,1) and (-6,6)

Answer 1

the slope formula with two points is

`m=\frac{y_2-y_1}{x_2-x_1_{}}`

where (x2,y2) is the rightmost point between them and (x1,y1) the other point

in this case (x2,y2)=(9,1)

so

`\begin{gathered} m=(1-6)/(9-(-6)) \\ m=(-5)/(9+6) \\ m=(-5)/(15) \\ m=(-1)/(3) \end{gathered}`

to find the slope of a perpendicular line you just change the sign of the slope and you reverse the number

so the slop of the perpendicular line is

`m=3`