Question

Why does


`3 * ((4 * 2) + 2 )/(4)`
is equivalent to

`3*2+3*(2)/(4)`
?

Answer 1

Explanation:

You must apply BODMAS to these types of equations

Brackets

Of

Division

Multiplication

Addition and

Subtraction

`3 * ((4 * 2) + 2)/(4)`

First, solve what's in the brackets

`3 * ((8) + 2)/( 4)`

Now we can simplify the numerator

`3 * (10)/(4)`

Since everything is simplified we can just multiply as usual and put the whole number over 1 to convert to a fraction

`(3)/(1) * (10)/(4)`

3*10=30

1*4=4

Therefore the answer is 30/4

And once it's simplified its 15/2

`3 * 2 + 3 * (2)/(4)`

Since there are no brackets in the original equation, we can add our own brackets which follows BODMAS

Our brackets will contain all the multiplication taking place

`(3 * 2) + (3 * (2)/(4) )`

Now we can simplify our brackets like we did before

`(6) + ( \ (3)/(1) * (2)/(4) )`

Here we have simplified 2*3 to 6 and made 3 into a fraction. We can once again just multiply our fractions like usual.

`6 + ( (6)/(4) )`

`6 + ( (3)/(2) )`

To make it easier we simplify the fraction

To add it together we need to change 6 into a fraction with the denominator of 2. When we do this we get 12/2

Now we can add

`(12)/(2) + (3)/(2)`

Once it is added we get 15/2