Step 1: Write out the equations and label them
![\begin{gathered} x-2y+32=8 \\ \text{ therefore} \\ x-2y=8-32=-24 \\ x-2y=-24-------(1) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/si97sy0kfbkms0aysudesrwuu423ha4188.png)
![\begin{gathered} 3y+z=12------(2) \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7inj8ytwl0jcx0s12z8omq0k09vjghgu2q.png)
![-2x+2z=-4------------------(3)](https://img.qammunity.org/2023/formulas/mathematics/college/jkujj78qcmortlvucxvwu8n24ar7llu6gv.png)
Step 2: From equation (1) we make isolate x to get equation (4)
![x=2y-24--------------(4)](https://img.qammunity.org/2023/formulas/mathematics/college/r6qrwj851l11p366v8iq7iv3u7asp7r0da.png)
Step 3: Substitute equation (4) into equation (3)
![\begin{gathered} -2(2y-24)+2z=-4 \\ \text{ Therefore} \\ 2y-24-z=2 \\ 2y-z=26----------(5) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ozps2bn041fwyskgekgcrssvwzr09goeuv.png)
Step 4: Add equation (5) to equation (2)
![\begin{gathered} 2y-z=26----------(5) \\ + \\ 3y+z=12------(2) \\ --------------------- \\ 5y=38 \\ y=(38)/(5) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/87o5jjhhvkgcq7rujrbvzyew5136mrs7jy.png)
Step 5: Substitute the value o f y = 38/5 into equation (5)
![\begin{gathered} 2((38)/(5))-z=26 \\ z=-(54)/(5) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/svzl0izfs0vszf1jy83hdiy1s2sd8c9yzg.png)
Step 6: Substitute the value of y = 38/5 into equation (1)
![\begin{gathered} x-2((38)/(5))=-24 \\ x=-(44)/(5) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gv3emwfx9jlvy2w2xu51gzdpn6zidnr6r6.png)
Hence, the solution is given by
x = -8.8, y = 7.6, and z = -10.8
d