Question

NEED HELP QUICK! Use the point-slope formula and the points from the line on the graph to write the linear equation in slope-intercept form. [Use 1, 6)]

Answer 1

Explanation:

the point- slope format is

y - y1 = m(x - x1)

m is the slope, and (x1, y1) is a point on the line.

the slope is the ratio "y coordinate difference / x coordinate difference" when going from one point to another.

for the 2 given points we see

x changes by +3 (from -2 to +1).

y changes by +9 ) from -3 to +6).

so, the slope m is +9/+3 = 3.

the point-slope equation is then (by using the suggested point) :

y - 6 = 3(x - 1)

and from there we can get to the slope-intercept form by simply rearranging things.

the general slope-intercept form is

y = mx + b

again, m is the slope, and b is the y-intercept (the y value when x = 0).

y - 6 = 3x - 3

y = 3x + 3

so, the fourth answer option is correct.

Answer 2

Last option, y = 3x + 3

Explanation:

Slope=∆y/∆x= (y2-y1)/x2-x1)

(1, 6) and (-2,-3)

(-2-6)/(-2-1) = -9/-3

Slope = 3

Point slope form; y-y1 = m(x-x1)

y - 6 = 3(x-1)

y - 6 = 3x - 3

y = 3x + 6 - 3

y = 3x + 3