Question

аAs a fundraiser, a club is selling posters. The printer charges a $15 set-up fee, plus $0.65 for each poster. The cost y in dollars to print xposters is given by y = 0.65x + 15.(a) What is the cost y in dollars to print 30 posters? To print 100 posters?(b) Find the number of posters x if the printer billed the club for costs of $210.(c) Write the information from parts (a) and (b) as three ordered pairs.(d) Use the data from part (c) to graph the equation for x 20.(a) The cost y to print 30 posters is and to print 100 posters is $(Type integers or decimals.)(b) The number of posters x when the cost is $210 is(Type a whole number.)(c) The ordered pairs are(Use a comma to separate answers as needed. Use integers or decimals for any numbers in the expression.)(d) Choose the correct graph below.A.BC.D.aQa400-400+400-400-Costs (in dollars)Costs (in dollars)Costs (in dollars)Costs (in dollars)LY0400Number of Posters0400Number of Posters0400Number of Posters0400Number of Posters

Answer 1

We have the following equation:

`y=0.65x+15`

where x denotes the n umber of posters and y the cost.

Part A.

In this case, we need to substitute x=30 and x=100 into the given equation. For x=30, we have

`\begin{gathered} y=0.65(30)+15 \\ y=19.5+15 \\ y=34.5 \end{gathered}`

Then, for x=100, we have

`\begin{gathered} y=0.65(100)+15 \\ y=65+15 \\ y=80 \end{gathered}`

Then a) The cost to print 30 posters is $34.5 and to print 100 is $80.

Part B.

In this case, we have that y=$210 and we need to find x. So, we have

`210=0.65x+15`

By subtracting 15 to both sides, we have

`195=0.65x`

Then, x is given by

`x=(195)/(0.65)=300`

Then, b) The number of posters x when the cost is $210 is 300

Part C.

From the above results, we have that

`\begin{gathered} \text{Part A: (30,34.5) (100,80)} \\ \text{Part B: (300,210)} \end{gathered}`

Therefore, the ordered pais are: (30,34.5), (100,80), (300,210)

Part D.

From the above information, the graph of the given equation is

By comparing our result with the given graphs, the answer is option C.