(a). Given value is,
![\begin{gathered} d=3052\text{ mm} \\ d=(3052)/(25.4) \\ d=120.2\text{ in} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/1m4jew1e33l19ji2cdjzcu9arj9f6uno6p.png)
Thus, the value from mm to in is 120.2 in.
(b). Given value is,
![\begin{gathered} P=25\text{psi} \\ P=25*6895 \\ P=172369\text{ Pa} \\ P=172.4*10^3\text{ Pa} \\ P=172.4\text{ kPa} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/qn450ov515rrpq10tmp18y6mvsnpt2md1p.png)
Thus, the value from psi to kPa is 172.4 kPa.
(c). Given value is,
![\begin{gathered} V=552cm^3 \\ V=(552)/(3785) \\ V=0.146\text{ gal} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/dky0mrd68et3bgnxvu2z8gjk778gf52e1x.png)
Thus, the value is 0.146 gal.
(d). Given value is,
![\begin{gathered} A=95mile^2 \\ A=95*2.59 \\ A=246.05km^2 \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/lm3tyr221qrdfu29df2hkhhvu13rzg5qj4.png)
Thus, the value is 246.05 km squared.
(e). Given value is,
![\begin{gathered} P=192BTUhr^(-1) \\ P=(192)/(3.41) \\ P=56.3\text{ W} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/4ro7rnpnhnmfszocwtuq8p12t03qairswt.png)
Thus, the value is 56.3 W.
(f). The given value is,
![\begin{gathered} P=\text{ 2225 Pa} \\ P=2225*0.000948 \\ P=2.11\text{ BTU} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/v6nqk502os4u3h78q6u5b9irg5ds4pluh2.png)
Thus, the value is 2.11 BTU.