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(2/3×2/3×2/3)+(1/9×1/9)×(8-2)

1 Answer

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We have


\mleft((2)/(3)*(2)/(3)*(2)/(3)\mright)+\mleft((1)/(9)*(1)/(9)\mright)*\mleft(8-2\mright)​

First we have to solve the operations inside the parentheses


((8)/(27))+((1)/(81))(6)

then we solve the multiplication


\begin{gathered} ((8)/(27))+((6)/(81)) \\ \end{gathered}

we need to have the same denominator in order to sum fractions


((8*81)+(6*27))/(27*81)=(648+162)/(2187)=(810)/(2187)=(10)/(27)

the expression simplified is 10/27

User McNultyyy
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