Answer:
The average speed is greater than the magnitude average velocity because the total distance is greater than the displacement of the man.
Step-by-step explanation:
First, let's write 2h 14 min as a decimal, so:
![\begin{gathered} 14\min *\frac{1\text{ hour}}{60\text{ min}}=0.23\text{ hours} \\ 2\text{ h 14 min = 2.23 hours} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/4cnjo8ju2cvjhyda70y4er7j0q7a9x7rw6.png)
Now, the average velocity is equal to the division of the displacement by time. The displacement is the straight-line distance, so the average velocity is:
![\text{Average velocity = }\frac{18\text{ miles}}{2.23\text{ hours}}=8.07\text{ miles per hour}](https://img.qammunity.org/2023/formulas/physics/college/kypzqim5s74scjjk44d022gse4z7mdraa9.png)
On the other hand, the average speed is the division of the total distance by time, so the average speed is:
![\text{Average speed = }\frac{26\text{ miles}}{2.23\text{ hours}}=11.66\text{ miles per hour}](https://img.qammunity.org/2023/formulas/physics/college/3k5onc03g2495iynvs0ybwby5nz1k42olq.png)
Therefore, the average speed is greater than the magnitude average velocity because the total distance is greater than the displacement of the man.