Question

Parallelogram ABCD will be translated so that D' will be located at (-1, 2). What would be the location ofpoint B'?yBсFD(-5, 0)(-3, 4)(-2,5)O (1.4)

Answer 1

To start we can define the initial point of D=

x= 4 and y=3

and we know that the new value D'=

x=-1 and y=2

So we can say that the point move, 5 units to the left on the axis x

(x-5) and 1 unit down on axis y (y-1)

So the other point will respect that formula, the new value of x

x'=x-5 and the new value of y'=y-1

So if the point B (initial) is x= 2 and y=5

B'= (x-5, y-1)= (2-5,5-1)=(-3,4)

So the answer is: (-3,4)