Question

I need help solving this problem please, I have noticed little explanations help me more with understanding

Answer 1

Given data :

`f(x)\text{ = 3x-1}`
`g(x)=(10)/(x)`
`h(x)=x^2+3`

a) f(5)

Put x = 5 in the expression of f(x)

`\begin{gathered} f(x)\text{ = 3x-1} \\ f(5)=3(5)-1 \\ f(5)=15-1 \\ f(5)=14 \end{gathered}`

f(5) = 14

b) g(65)

put x = 65

`\begin{gathered} g(x)=(10)/(x) \\ g(65)=(10)/(65) \\ g(65)=(2)/(13) \end{gathered}`

g(65) =2/13

c) h(-2)

Put x = -2 in the expression of h(x)

`\begin{gathered} h(x)=x^2+3 \\ h(-2)=(-2)^2+3 \\ h(-2)=4+3 \\ h(-2)=7 \end{gathered}`

h(-2) = 7

d) f(x) = 20

Put f(x)=20 in the expression of f(x)

`\begin{gathered} f(x)\text{ = 3x-1} \\ 20=3x-1 \\ 3x=20+1 \\ 3x=21 \\ x=(21)/(3) \\ x=7 \end{gathered}`

x = 7

Answer:

a) f(5) = 14

b) g(65)=2/13

c) h(-2)=7

d) x=7