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8x + y = -16-3x + y = -5solve for x and y

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Answer:

x=-1, y=-8.

Step-by-step explanation:

Given the system of equations:


\begin{gathered} 8x+y=-16 \\ -3x+y=-5 \end{gathered}

To eliminate y, subtract:


\begin{gathered} 8x-(-3x)=-16-(-5) \\ 8x+3x=-16+5 \\ 11x=-11 \end{gathered}

Divide both sides by 11:


\begin{gathered} (11x)/(11)=-(11)/(11) \\ x=-1 \end{gathered}

Next, substitute the value of x into any of the equations to solve for y:


\begin{gathered} 8x+y=-16 \\ 8(-1)+y=-16 \\ -8+y=-16 \\ y=-16+8 \\ y=-8 \end{gathered}

The solution to the system of equations is x=-1, y=-8.

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