Question

Find the x-intercept and y-intercept of the line.7x+4y=-28* -intercept: 08coХ5?y -intercept:

Answer 1

The given equation of the line is:

`7x+4y=-28`

It is required to find the x-intercept and the y-intercept.

To find the x-intercept, substitute y=0 into the equation and find x:

`\begin{gathered} 7x+4(0)=-28 \\ \Rightarrow7x=-28 \\ \text{ Divide both sides by }7: \\ \Rightarrow(7x)/(7)=(-28)/(7) \\ \Rightarrow x=-4 \end{gathered}`

Hence, the x-intercept is -4.

To find the y-intercept, substitute x=0 into the equation and find y:

`\begin{gathered} 7(0)+4y=-28 \\ \Rightarrow4y=-28 \\ \text{ Divide both sides by }4: \\ \Rightarrow(4y)/(4)=(-28)/(4) \\ \Rightarrow y=-7 \end{gathered}`

The y-intercept is -7.

Answers:

x-intercept: -4

y-intercepe: -7