Question

How many moles are in 9.62 x 10^23 atoms of iron?

Answer 1

1.598moles

Explanations:

According to the Avogadro's constant;

1 mole of an atom = 6.02 * 10^23 molecules

If there are 9.62 x 10^23 atoms of iron, the number of moles it contains is expressed as:

`\begin{gathered} mole\text{ of Fe}=(9.62*10^(23))/(6.02*10^(23)) \\ moles\text{ of Fe}=(9.62)/(6.02) \\ moles\text{ of Fe}=1.598moles \end{gathered}`

Hence the required moles of iron is 1.598moles