Question

What is the distance between a points (3,4) and (-2,-2) (round to the nearest 10th, if necessary) distance between the points (three, four) and (-2, -2) is blank units?

Answer 1

The coordinates given in the question are

`\begin{gathered} (x_1,y_1)\Rightarrow(3,4) \\ (x_2,y_2\Rightarrow(-2,-2) \end{gathered}`

Concept:

The distance between two points of a line is given below as

`d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}`

By substituting the values, we will have

`\begin{gathered} d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ d=\sqrt[]{(-2-3)^2+(-2-4)^2} \\ d=\sqrt[]{(-5)^2+(-6)^2} \\ d=\sqrt[]{25+36} \\ d=\sqrt[]{61} \\ d=7.8\text{ units} \end{gathered}`

Hence,

The final answer is

`\Rightarrow7.8`