Question

Times for an ambulance to respond to a medical emergency in a certain town are normally distributed with a mean of 450 secondsand a standard deviation of 50 seconds.Suppose there are 97 emergencies in that town.In about how many emergencies are the response times expected between 400 seconds and 500 seconds?

Answer 1

Times for an ambulance to respond to a medical emergency in a certain town are normally distributed with a mean of 450 seconds

and a standard deviation of 50 seconds.

Suppose there are 97 emergencies in that town.

In about how many emergencies are the response times expected between 400 seconds and 500 seconds?

For 400 sec

z=[(400-450)/50]=-1

For 500 sec

z=(500-450)/50=1

using a z-score calculator

P=0.68269

multiply the probability by the number of emergencies

0.68269*97=65.96

therefore

the answer is 66