Question

Hi, I was absent today in class and I really need help with question 4I will be much appreciated if you show work and the step so I can be more understanding thank you!

Answer 1

4.

`4.83^x=29.1`

We can use logarithms to solve this problem.

Start by taking the common logarithm of each side:

`\log (4.83^x)=\log (29.1)`

Apply the power property of logarithms:

`x\cdot\log (4.83)=\log (29.1)`

And solve for x:

`\begin{gathered} x=(\log 29.1)/(\log 4.83)=(1.46)/(0.68) \\ x=2.14 \end{gathered}`