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I need help question

User Ipartola
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1 Answer

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The given function f is given by:


f(x)=(1)/((x^5-7x+6)^8)
\begin{gathered} \text{ Let }u\text{ be a function given by:} \\ u(x)=x^5-7x+6 \end{gathered}

Therefore,


(du)/(dx)=5x^4-7

and


f(x)=(1)/(u^8)

Therefore,


f^(\prime)(x)=(df)/(du)*(du)/(dx)

Since f = 1/u⁸, it follows that:


(df)/(du)=-(8)/(u^9)

Therefore,


\begin{gathered} f^(\prime)(x)=-(8)/(u^9)*(5x^4-7) \\ =-(8)/((x^5-7x+6)^9)*(5x^4-7) \end{gathered}

Therefore,


f^(\prime)(x)=(8(7-5x^4))/((x^5-7x+6)^9)

.

User Hamed Rezaee
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