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Ghokun · Answer 1 · 2023-07-02T11:14:56+0000

According to the properties of a logarithm, when we have a multiplication in the argument of this function we can write it as the sum of logartihms, like this:

$\log_a(x* y)=\operatorname{\log}_a(x)+\operatorname{\log}_a(y)$

Then, we can apply this property to the given logarithm to get:

$\log_3(81x)=\log_3(81)+\log_3(x)$

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