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write an equation in slope intercept form form for the line that passes through (-3,5) and is perpendiculat to the graph of the line y=1/3x+4

1 Answer

5 votes

We will solve as follows:

*First we will determine the slope of the new line:

From theorem we have that two perpendicular lines follow this rule:


m_1=-(1)/(m_2)

So, the slope of the new line is:


m=-(1)/(((1)/(3)))\Rightarrow m=-3

*Second, we replace the values of the point and the slope in the following expression:


y-y_1=m(x-x_1)

That is:


y-5=-3(x+3)

Now, we solve for y:


y-5=-3x-9\Rightarrow y=-3x-4

So the equation of the line that fulfills the parameters is:


y=-3x-4

User Vumaasha
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