Question

Find the indicated values.A3x + 12IMB7x – 8сX=AB=

Answer 1

Lines AB and BC are intersecting tangents from the same circle and are thus equal.

AB = BC

3x + 12 = 7x - 8 || Adding 8 while subtracting 3x from both sides gives:

7x - 3x = 12 + 8

4x = 20 || Dividing both sides by 4 gives

`\begin{gathered} (4x)/(4)=(20)/(4) \\ x=5 \end{gathered}`

Therefore, x = 5

AB = 3x + 12 || where x = 5

AB = 3(5) + 12

AB = 15 + 12 = 27

AB = 27