Question

THE LAST PART TO THE QUESTION ONLYPLEASE DO NPT ANSWER THE FIRST 2 PARTS ONLY THE LAST POART

Answer 1

#12 c

The given expression is

`\ln (\frac{e^(6x)(x^2+14)^{(1)/(9)}}{(x-4)^4})`

We will use the rule of expansion of ln

`\ln ((ab)/(c))=la(a)+\ln (b)-\ln (c)`
`\ln (e^(6x))+\ln (x^2+14)^{(1)/(9)}-\ln (x-4)^4`

Use the rule

`\begin{gathered} \ln (a)^n=n\ln (a) \\ \ln (e^n)=n \end{gathered}`
`6x+(1)/(9)\ln (x^2+14)-4\ln (x-4)`

The answer is

`\ln (\frac{e^(6x)(x^2+14)^{(1)/(9)}}{(x-4)^4})=6x+(1)/(9)\ln (x^2+14)-4\ln (x-4)`