Question

As I am brand new to this subject/branch of mathematics, please explain thoroughly, step by step on how to complete this *Ignore the last answer option

Answer 1

Given the expression:

`(3x-4y^2)(3x+4y^2)`

From the difference of squares identity:

`(a+b)(a-b)=a^2-b^2`

From the problem, we identify:

`\begin{gathered} a=3x \\ b=4y^2 \end{gathered}`

Finally, using the identity:

`\begin{gathered} (3x-4y^2)(3x+4y^2)=(3x)^2-(4y^2)^2 \\ \\ \therefore9x^2-16x^4 \end{gathered}`