Solution
We first draw the diagram of the problem
From the diagram above,
A is used to denote the first station;
B is used to denote the second station
C is used to denote the camper location
x is the distance between the first station and the camper
y is the distance between the second station and the camper
Therefore, we want to find x and y
We complete the above triangle by finding the remaining two angles
Using the Sine Rule

From the triangle above
![\begin{gathered} (x)/(\sin80)=(100)/(\sin 29) \\ \text{cross multiply} \\ x*\sin 29=100*\sin 80 \\ x\sin 29=100\sin 80 \\ x=(100\sin 80)/(\sin 29) \\ x=203.1328818 \\ x=203.13\operatorname{km} \end{gathered}]()
Thus, the distance of the camper from the first station is 203.13km
Now, we are left with finding the distance of the camper from the second station
![\begin{gathered} (y)/(\sin71)=(100)/(\sin 29) \\ \text{cross multiply} \\ y*\sin 29=100*\sin 71 \\ y\sin 29=100\sin 71 \\ y=(100\sin 71)/(\sin 29) \\ y=195.0288394 \\ y=195.03\operatorname{km} \end{gathered}]()
Therefore, the distance of the camper from the second station is 195.03km