We have the x-intercepts of the function x = -6 & x = 3, and the function passes y (0, -9).
We use the expression:

Here a is a number, and r1 & r2 will be our x intercepts. So we replace them in the function:

Since we have the y intercept given to us by the point (0, -9), we do as follows:

So, we replace the values in our function:

So, that's our quadratic function that passes by (0, -9) and has x-intercepts at x = -6 & x = 3.
